(x+4)^2-20/4

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Solution for (x+4)^2-20/4 equation: 


x in (-oo:+oo)

(x+4)^2-(20/4) = 0

(x+4)^2-5 = 0

(x+4)^2-5 = 0

x^2+8*x+11 = 0

x^2+8*x+11 = 0

x^2+8*x+11 = 0

DELTA = 8^2-(1*4*11)

DELTA = 20

DELTA > 0

x = (20^(1/2)-8)/(1*2) or x = (-20^(1/2)-8)/(1*2)

x = (2*5^(1/2)-8)/2 or x = (-2*5^(1/2)-8)/2

(x-((-2*5^(1/2)-8)/2))*(x-((2*5^(1/2)-8)/2)) = 0

(x-((-2*5^(1/2)-8)/2))*(x-((2*5^(1/2)-8)/2)) = 0

( x-((-2*5^(1/2)-8)/2) )

x-((-2*5^(1/2)-8)/2) = 0 // + (-2*5^(1/2)-8)/2

x = (-2*5^(1/2)-8)/2

( x-((2*5^(1/2)-8)/2) )

x-((2*5^(1/2)-8)/2) = 0 // + (2*5^(1/2)-8)/2

x = (2*5^(1/2)-8)/2

x in { (-2*5^(1/2)-8)/2, (2*5^(1/2)-8)/2 }

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